Q65 / 160 · AP EAMCET 2024 (23 May Shift 1) · Mathematics
$\cosh (\log 4)=$
- A$\frac{8}{17}$
- Correct answerB$\frac{17}{8}$
- C0
- D$\frac{9}{8}$
Solution
$\cos h(\log 4)=\frac{e^{\log 4}+e^{-\log 4}}{2}=\frac{4+\frac{1}{4}}{2}=\frac{17}{8}$.
Hence, the correct answer is option: 'B'.