Q109 / 160 · AP EAMCET 2024 (21 May Shift 2) · Mathematics

$\int \frac{\sin ^6 x}{\cos ^8 x} d x=$

  • A
    $\tan^7 x+c$
  • Correct answer
    B
    $\frac{\tan^7 x}{7}+c$
  • C
    $\frac{\tan ^7 x}{3}+c$
  • D
    $\sec ^7 x$

Solution

$\int \frac{\sin ^6 x}{\cos ^8 x} d x=\int \tan ^6 x \sec ^2 x d x=\frac{\tan ^7 x}{7}+c$.

Hence, the correct answer is option: 'B'.

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