Q99 / 160 · AP EAMCET 2024 (19 May Shift 2) · Mathematics

$\lim _{x \rightarrow 3} \frac{x^3-27}{x^2-9}=$

  • A
    $\frac{3}{2}$
  • Correct answer
    B
    $\frac{9}{2}$
  • C
    $3$
  • D
    $2$

Solution

$\lim _{x \rightarrow 3} \frac{x^3-27}{x^2-9} = \lim _{x \rightarrow 3} \frac{(x-3)\left(x^2+9+3 x\right)}{(x-3)(x+3)}=\frac{9}{2}$.

Hence, the correct answer is option: 'B'.

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