Q64 / 160 · AP EAMCET 2023 (18 May Shift 1) · Mathematics
$\log (\cosh 3+\sinh 3)+\log (\cosh 3-\sinh 3)=$
- A$1$
- B$2$
- C$3$
- Correct answerD$0$
Solution
$\log (\cosh 3+\sin h 3)+\log (\cosh 3-\sinh 3)$
$\begin{aligned} & =\log \left(\frac{\mathrm{e}^3+\mathrm{e}^{-3}}{2}+\frac{\mathrm{e}^3 \mathrm{e}^{-3}}{2}\right)+\log \left(\frac{\mathrm{e}^3+\mathrm{e}^{-3}}{2}-\frac{\mathrm{e}^3-\mathrm{e}^{-3}}{2}\right) \\ & =\log \left(\mathrm{e}^3\right)+\log \left(\mathrm{e}^{-3}\right) \\ & =3-3=0\end{aligned}$
Hence, the correct answer is option: 'D'.