$$ \lim _{x \rightarrow 0}\left(\frac{4^x-1}{2^x-1}-\frac{\sqrt{4+3 x}-2}{x}\right)= $$

• A

  0
• Correct answer
  B

  $\frac{5}{4}$
• C

  $\log 2-3$
• D

  $\frac{\log 4}{\log 2}-3$

Hence, the correct answer is option: 'B'.