Q98 / 150 · MHT CET 2022 (08 Aug Shift 1) · Mathematics

$\int_{-1}^1 \log \left(\frac{2-x}{2+x}\right) d x=$

  • A
    1
  • B
    -1
  • Correct answer
    C
    0
  • D
    2

Solution

$\begin{aligned} & \int_{-1}^1 \log \left(\frac{2-x}{2+x}\right) \mathrm{d} x=0 \\ & \because \log \left(\frac{2-x}{2+x}\right) \text { is an odd function. }\end{aligned}$

Hence, the correct answer is option: 'C'.

Relevant Questions