Q96 / 150 · MHT CET 2021 (21 Sep Shift 1) · Mathematics
$$
\int e^{\tan x}\left(\sec ^2 x+\sec ^3 x \sin x\right) d x=
$$
- Correct answerA$\tan x \cdot e^{\tan x}+c$
- B$(1+\tan x) e^{\tan }+c$
- C$\sec x \cdot e^{\tan x}+c$
- D$\mathrm{e}^{\tan x+\tan x}+c$
Solution
Let
$$
I=\int e^{\tan x}\left(\sec ^2 x+\sec ^3 x \sin x\right) d x=\int e^{\tan x}\left(\sec ^2 x\right)+(1+\tan x) d x
$$
Put $\tan \mathrm{x}=\mathrm{t} \Rightarrow \sec ^2 \mathrm{xdx}=\mathrm{dt}$
$$
\therefore I=\int \mathrm{e}^{\mathrm{t}}(1+\mathrm{t}) \mathrm{dt}=\mathrm{e}^{\mathrm{t}}(\mathrm{t})+\mathrm{c}=\mathrm{e}^{\tan \mathrm{x}}(\tan \mathrm{x})+\mathrm{c}
$$
Hence, the correct answer is option: 'A'.