Q95 / 150 · MHT CET 2009 · Mathematics
$\sim(\sim p \rightarrow q) \equiv$
- A$p \wedge \sim q$
- B$\sim p \wedge q$
- Correct answerC$\sim p \wedge \sim q$
- D$\sim p \vee \sim q$
Solution
$\sim(\sim p \rightarrow q)=\sim p \wedge \sim q$
Hence, the correct answer is option: 'C'.