Q110 / 120 · VITEEE 2013 · Physics
Two waves $y_{1}=A_{1} \sin \left(\omega t-\beta_{1}\right)$ and $y_{2}=A_{2} \sin \left(\omega t-\beta_{2}\right)$ superimpose to form a resultant wave whose amplitude is
- A$A_{1}+A_{2}$
- B$\left|\mathrm{A}_{1}+\mathrm{A}_{2}\right|$
- C$\sqrt{A_{1}^{2}+A_{2}^{2}-2 A_{1} A_{2} \sin \left(\beta_{1}-\beta_{2}\right)}$
- Correct answerD$\sqrt{A_{1}^{2}+A_{2}^{2}+2 A_{1} A_{2} \cos \left(\beta_{1}-\beta_{2}\right)}$
Solution
Amplitudes $\mathrm{A}_{1}$ and $\mathrm{A}_{2}$ are added as vectors. Angle between the two vectors is the phase difference $\left(\beta_{1}-\beta_{2}\right)$ between them.
$\therefore$ Resultant wave,
$\mathrm{R}=\sqrt{\mathrm{A}_{1}^{2}+\mathrm{A}_{2}^{2}+2 \mathrm{~A}_{1} \mathrm{~A}_{2} \cos \left(\beta_{1}-\beta_{2}\right)}$
Hence, the correct answer is option: 'D'.