Two vibrating strings ' A ' and ' B ' produce beats of frequency 8 Hz. The beat frequency is found to reduce to 4 Hz if the tension in the string 'A'…

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Two vibrating strings ' A ' and ' B ' produce beats of frequency 8 Hz. The beat frequency is found to reduce to 4 Hz if the tension in the string 'A' is slightly reduced. If the original frequency of A is 320 Hz, then the frequency of B ' is

MARKS Content Team · Accepted Answer

Correct answer: (B) 312 Hz. The frequency of the string, A, f_A =320 Hz Frequency of string B=f_B ​ Beat’s frequency,n=8 Hz. Beat's Frequency is given as: n=f_A-f_B⇒8=f_A-f_B=320-f_B⇒f_B=312 Hz & 328 Hz Frequency decreases with a decrease in the tension in a string. This is because the frequency is directly proportional to the square root of the tension. It is given as: f∝T ​ Hence, the beat frequency cannot be 328 Hz∴f_B=312 Hz.

Two vibrating strings ' $A$ ' and ' $B$ ' produce beats of frequency $8 Hz$ . The beat frequency is found to reduce to $4 Hz$ if the tension in the string $' A'$ is slightly reduced. If the original frequency of $A$ is $320 Hz$ , then the frequency of $B$ ' is

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