Q152 / 160 · TS EAMCET 2020 (09 Sep Shift 1) · Physics

Two straight conducting rails form a right angle as shown below. A conducting bar in contact with the rails starts at the vertex at time t=0 and moves with constant velocity of v=5 m s-1 along them. A magnetic field with B=0.1 T is directed out of the page. The absolute value of the emf around the triangle at the time t=4 s will be?
Figure

  • A
    10 V
  • B
    15 V
  • Correct answer
    C
    20 V
  • D
    30 V

Solution

Given: Velocity of conducting bar v=5 m s-1

Magnetic field B=0.1 T pointing out of the page.

For the given time interval distance travelled by the bar d=v×t=4×5=20 m

In a time t=4 s, the bar will travel a distance equal to 20 m as seen from the diagram below.

Figure..

Now induced emf is given as e=Bvl

e=0.1×5×40=20 V

Hence, the correct answer is option: 'C'.

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