Two stones are thrown up simultaneously from the edge of cliff with initial speeds v and 2v. The relative position of the second stone with respect to…

Question

Two stones are thrown up simultaneously from the edge of cliff with initial speeds v and 2v. The relative position of the second stone with respect to first varies with time till both the stones strike the ground as

MARKS Content Team · Accepted Answer

Correct answer: (B) First linearly then parabolically. Initially when both are in air, the relative acceleration between them is zero. Therefore, relative position verus-time graph is a straight line. S_1=vt-1/2gt^2 S_2=2vt-1/2gt^2 S_21=S_2-S_1 S_21=vt Once the first ball reaches the ground, its acceleration becomes zero. Therefore, the relative acceleration is now g and the graph is parabolic. S_2=2vt-1/2gt^2

Two stones are thrown up simultaneously from the edge of cliff with initial speeds $v$ and $2 v$ . The relative position of the second stone with respect to first varies with time till both the stones strike the ground as

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