Q224 / 225 · JEE Main 2003 · Physics
Two stones are projected from the top of a cliff $\mathrm{h}$ metres high, with the same speed $\mathrm{u}$, so as to hit the ground at the same spot. If one of the stones is projected at an angle $\theta$ to the horizontal then the $\theta$ equals
- Correct answerA$\mathrm{u} \sqrt{\frac{2}{\mathrm{gh}}}$
- B$\sqrt{\frac{2 \mathrm{u}}{\mathrm{gh}}}$
- C$2 \mathrm{~g} \sqrt{\frac{\mathrm{u}}{\mathrm{h}}}$
- D$2 \mathrm{~h} \sqrt{\frac{\mathrm{u}}{\mathrm{g}}}$
Solution
$\mathrm{R}=\mathrm{u} \sqrt{\frac{2 \mathrm{~h}}{\mathrm{~g}}}=(\mathrm{u} \cos \theta) \times \mathrm{t}$
$t=\frac{1}{\cos \theta} \sqrt{\frac{2 h}{g}}$
Hence, the correct answer is option: 'A'.