Q128 / 180 · JIPMER 2015 · Physics
Two small balls, each carrying a charge $q$ are suspended by equal insulator strings of length 1 m from the hook of a stand. This arrangement is carried in a satellite in space. The tension in each string will be
- A$\frac{1}{4 \pi \varepsilon_0} \frac{q}{l^2}$
- Correct answerB$\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{4 l^2}$
- C$\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{l^2}$
- D$\frac{1}{\left(4 \pi \varepsilon_0\right)} \frac{q}{l}$
Solution
Suppose, $T$ be the tension in the spring $T$. Also in the satellite, two balls will be in a straight line. So, force acting on the balls
$F=\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{(2 l)^2}$ $\ldots$ (i)
This force will be balanced by tension in the string.
i.e.,
$T=F$ $\ldots$ (ii)
Now, from Eqs. (i) and (ii), we get
$T=\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{4 l^2}$
Hence, the correct answer is option: 'B'.