Q147 / 150 · JEE Main 2006 · Physics

Two rigid boxes containing different ideal gases are placed on a table. Box A contains one mole of nitrogen at temperature $T_0$, while Box $B$ contains one mole of helium at temperature $(7 / 3) T_0$. The boxes are then put into thermal contact with each other and heat flows between them until the gases reach a common final temperature. (Ignore the heat capacity of boxes). Then, the final temperature of the gases, $T_f$, in terms of $T_0$ is

  • A
    $\mathrm{T}_{\mathrm{f}}=\frac{5}{2} \mathrm{~T}_0$
  • B
    $\mathrm{T}_{\mathrm{f}}=\frac{3}{7} \mathrm{~T}_0$
  • C
    $\mathrm{T}_{\mathrm{f}}=\frac{7}{3} \mathrm{~T}_0$
  • Correct answer
    D
    $T_f=\frac{3}{2} T_0$

Solution

$\Delta \mathrm{U}=0$ $\Rightarrow \frac{3}{2} \mathrm{R}\left(\mathrm{T}_{\mathrm{f}}-\mathrm{T}_0\right)+1 \times \frac{5}{2} \mathrm{R}\left(\mathrm{T}_{\mathrm{f}}-\frac{7}{3} \mathrm{~T}_0\right)=0$ $\mathrm{~T}_{\mathrm{f}}=\frac{3}{2} \mathrm{~T}_0$

Hence, the correct answer is option: 'D'.

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