. Two points are located at a distance of 10 ~m and 15 ~m from the source of oscillation. The period of oscillation is 0.05 sec and the velocity of the wave is 300 ~m / sec . What is the phase difference between the oscillations of two points?

Correct answer: (C) (2 π)/3. Phase difference φ=(2 π)/(λ) × path difference =(2 π)/15 ×(15-10) \λ=v T=300 × 0.05 ~m\ =(2 π)/5

Q120 / 199 · NEET 2008 (Mains) · Physics

. Two points are located at a distance of $10 \mathrm{~m}$ and $15 \mathrm{~m}$ from the source of oscillation. The period of oscillation is $0.05 \mathrm{sec}$ and the velocity of the wave is $300 \mathrm{~m} / \mathrm{sec}$. What is the phase difference between the oscillations of two points?

A
$\frac{\pi}{6}$
B
$\frac{\pi}{3}$
Correct answer
C
$\frac{2 \pi}{3}$
D
$\pi$

Solution

Phase difference $\phi=\frac{2 \pi}{\lambda} \times$ path difference $$ \begin{aligned} & =\frac{2 \pi}{15} \times(15-10) \quad\{\lambda=v T=300 \times 0.05 \mathrm{~m}\} \\ & =\frac{2 \pi}{5} \end{aligned} $$

Hence, the correct answer is option: 'C'.

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