Two point charges $q_1\left(\sqrt{10} \mathrm{\mu C}\right)$ and $q_2\left(-25 \mathrm{\mu C}\right)$ are placed on the $x$ -axis at $x=1 \mathrm{m}$ and $x=4 \mathrm{m}$ respectively. The electric field $\left(\text{in}\mathrm{ }\mathrm{V}/\mathrm{m}\right)$ at a point $y=3 \mathrm{m}$ on $y$-axis is,

$\left[\text{Take} \frac{1}{4\pi {ϵ}_0}=9\times {10}^9 \mathrm{N} {\mathrm{m}}^2{\mathrm{C}}^{-2}\right]$

• A

  $\left(-81\mathrm{ }\widehat{\mathrm{i}}+81\mathrm{ }\widehat{\mathrm{j}}\right)\times {10}^2$
• B

  $\left(81\mathrm{ }\widehat{\mathrm{i}}-81\mathrm{ }\widehat{\mathrm{j}}\right)\times {10}^2$
• C

  $\left(-63\mathrm{ }\widehat{\mathrm{i}}+27\mathrm{ }\widehat{\mathrm{j}}\right)\times {10}^2$
• Correct answer
  D

  $\left(63\widehat{\mathrm{i}}-27\widehat{\mathrm{j}}\right)\times {10}^2$

Hence, the correct answer is option: 'D'.