Two particles X and Y having equal charges are being accelerated through the same potential difference. Thereafter, they enter normally in a region of…

Question

Two particles X and Y having equal charges are being accelerated through the same potential difference. Thereafter, they enter normally in a region of uniform magnetic field and describes circular paths of radii R_1 and R_2 respectively. The mass ratio of X and Y is :

MARKS Content Team · Accepted Answer

Correct answer: (B) R1R2^2. Energy gained due to potential difference by charged particle: KE=qV Relation between momentum & kinetic energy: p=√2mKE Now, radius of the circular path under magnetic field will be given by, R=mv/qB=p/qB=√(2m(KE))qB=√2mqVqB Therefore, R∝√m⇒m∝R^2 ⇒m_1 m_2=R1R2^2

Two particles $X$ and $Y$ having equal charges are being accelerated through the same potential difference. Thereafter, they enter normally in a region of uniform magnetic field and describes circular paths of radii $R_{1}$ and $R_{2}$ respectively. The mass ratio of $X$ and $Y$ is :

Solution

Relevant Questions

Two particles X and Y having equal charges are being accelerated through the same potential difference. Thereafter, they enter normally in a region of uniform magnetic field and describes circular paths of radii R1 and R2 respectively. The mass ratio of X and Y is :

Solution

Relevant Questions

Two particles $X$ and $Y$ having equal charges are being accelerated through the same potential difference. Thereafter, they enter normally in a region of uniform magnetic field and describes circular paths of radii $R_{1}$ and $R_{2}$ respectively. The mass ratio of $X$ and $Y$ is :