Two parallel large thin metal sheets have equal surface charge densities (σ=26.4 × 10^-12 C / m^2 ) of opposite signs. The electric field between these sheets is

Correct answer: (C) 3 ~N / C. Electric field between the sheets is E=(σ)/(ε_0)=frac26.4 × 10^-128.85 × 10^-12 ≈ 3 ~N / C .

Q118 / 180 · AIIMS 2006 · Physics

Two parallel large thin metal sheets have equal surface charge densities $\left(\sigma=26.4 \times 10^{-12} \mathrm{C} / \mathrm{m}^2\right)$ of opposite signs. The electric field between these sheets is

A
$1.5 \mathrm{~N} / \mathrm{C}$
B
$1.5 \times 10^{-10} \mathrm{~N} / \mathrm{C}$
Correct answer
C
$3 \mathrm{~N} / \mathrm{C}$
D
$3 \times 10^{-10} \mathrm{~N} / \mathrm{C}$.

Solution

Electric field between the sheets is $$ E=\frac{\sigma}{\varepsilon_0}=\frac{26.4 \times 10^{-12}}{8.85 \times 10^{-12}} \approx 3 \mathrm{~N} / \mathrm{C} \text {. } $$

Hence, the correct answer is option: 'C'.

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