Two paper screens A and B are separated by 150 m. A bullet pierces A and then B. The hole in B is 15 cm below the hole in A. If the bullet is…

Question

Two paper screens A and B are separated by 150 m. A bullet pierces A and then B. The hole in B is 15 cm below the hole in A. If the bullet is traveling horizontally at the time of hitting A, then the velocity of the bullet at A is: g=10 m s^(-2)

MARKS Content Team · Accepted Answer

Correct answer: (D) 500√3 m s^(-1). The bullet exhibits horizontal projectile motion. Displacement of bullet in vertical direction,y=15 cm=0.15 m Displacement of bullet in horizontal direction,x=150 m The equation of trajectory, y=(gx^2)/(2u^2) ⇒0.15=(10×150^2)/(2u^2) ⇒2u^2=(10×150^2)/0.15 ⇒u=500√3 ms^(-1)

Two paper screens A and B are separated by $150 m$ . A bullet pierces A and then B. The hole in B is $15 cm$ below the hole in A. If the bullet is traveling horizontally at the time of hitting A, then the velocity of the bullet at A is: $(g = 10 m s^{- 2})$

Solution

Relevant Questions

Two paper screens A and B are separated by 150 m. A bullet pierces A and then B. The hole in B is 15 cm below the hole in A. If the bullet is traveling horizontally at the time of hitting A, then the velocity of the bullet at A is: g=10 m s-2

Solution

Relevant Questions

Two paper screens A and B are separated by $150 m$ . A bullet pierces A and then B. The hole in B is $15 cm$ below the hole in A. If the bullet is traveling horizontally at the time of hitting A, then the velocity of the bullet at A is: $(g = 10 m s^{- 2})$