Two objects are projected with same velocity u however at different angles α and β with the horizontal. If α +β= 90°, the ratio of horizontal range of…

Question

Two objects are projected with same velocity u however at different angles α and β with the horizontal. If α +β= 90°, the ratio of horizontal range of the first object to the 2^nd object will be :

MARKS Content Team · Accepted Answer

Correct answer: (D) 1 : 1. Given: α+β=90° Range of the first projectile: R_1=(u^2sin2α)/g Range of the second projectile: R_2=(u^2sin2β)/g=(u^2sin(180°-2α))/g=(u^2sin2α)/g As we can see, both are equal. R_1=R_2 Therefore, R_1:R_2=1:1

Two objects are projected with same velocity $u$ however at different angles $α$ and $β$ with the horizontal. If $α + β = 90 °$ , the ratio of horizontal range of the first object to the $2^{nd}$ object will be :

Solution

Relevant Questions

Two objects are projected with same velocity u however at different angles α and β with the horizontal. If α +β= 90°, the ratio of horizontal range of the first object to the 2nd object will be :

Solution

Relevant Questions

Two objects are projected with same velocity $u$ however at different angles $α$ and $β$ with the horizontal. If $α + β = 90 °$ , the ratio of horizontal range of the first object to the $2^{nd}$ object will be :