Two negative charges of equal magnitude are located in $x y$-plane as shown below in the figure. The direction of the electric field at point $P$ is

• A

  along positive, $x$-direction
• Correct answer
  B

  along negative, $x$-direction
• C

  along positive, $y$-direction
• D

  along negative, $y$-direction

Solution

As $E_1=E_2$ and charges are symmetrically placed on $Y$-axis,
Resultant lies along angle bisector of $\mathbf{E}_1$ and $\mathbf{E}_2$. i.e., along negative $X$-axis.

Hence, the correct answer is option: 'B'.