Q26 / 108 · NTA Abhyas (JEE Main) 2020 · Mathematics · Probability

Two natural numbers are randomly chosen and multiplied, then the chance that their product is divisible by $3$ is

A
$\frac{4}{9}$
Correct answer
B
$\frac{5}{9}$
C
$\frac{2}{3}$
D
$\frac{1}{9}$

Solution

Let

E

be the event that a natural number randomly chosen is not divisible by

3,

then

P (E) = \frac{2}{3}

P

(required event)

= 1 - P (E E) = 1 - {(\frac{2}{3})}^{2} = \frac{5}{9}

Hence, the correct answer is option: 'B'.

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