Q43 / 92 · NTA Abhyas (JEE Main) 2020 · Mathematics · Parabola

Two mutually perpendicular tangents of the parabola y2=4ax at the points Q1 and Q2 on it meet its axis in P1 and P2. If S is the focus of the parabola, then the value of 1SP1+1SP2-1 is equal to

  • A
    a4
  • B
    a2
  • Correct answer
    C
    a
  • D
    2a

Solution

Let Q1=at12,2at1 & Q2=at22,2at2 are points of contact of the tangents passing through P1 & P2 respectively.
⇒P1=-at12,0 & P2=-at22,0
⇒P1S=a+at12 & P2S=a+at22
⇒1PS1+1PS2=1a+at12+1a+at22=1a+at12+1a+a-1t12
=1a

Hence, the correct answer is option: 'C'.

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