Q72 / 75 · JEE Main 2025 (3 Apr Shift 2) · Physics
Two monochromatic light beams have intensities in the ratio 1:9. An interference pattern is obtained by these beams. The ratio of the intensities of maximum to minimum is
- A$8: 1$
- B$9: 1$
- C$3: 1$
- Correct answerD$4: 1$
Solution
$\frac{I_{\max }}{I_{\min }}=\frac{\left(\sqrt{I_1}+\sqrt{I_2}\right)^2}{\left(\sqrt{I_1}-\sqrt{I_2}\right)^2} \Rightarrow \frac{(4)^2}{(2)^2} \Rightarrow \frac{16}{4}=4$
Hence, the correct answer is option: 'D'.