Q26 / 150 · MHT CET 2018 · Chemistry

Two moles of an ideal gas are allowed to expand from a volume of $10 d m^{3}$ to $2 m^{3}$ at $300 K$ against a pressure of $101.325 K P a.$ Calculate the work done.

Correct answer
A
$- 201.6 k J$
B
$13.22 k J$
C
$- 810.6 k J$
D
$- 18.96 k J$

Solution

V_{1} = 10 {dm}^{3} = 1 0^{- 2} m^{3}

V_{2} = 2 m^{3}

V_{2} - V_{1} = (2 - 10^{- 2})

= 1.99 m^{3}

P = 101.325 \times 1 0^{3} pa

W = - P_{e x t} . Δ V

W = - 101.325 \times 1 0^{3} (1.99)

= 201.6 k J

Hence, the correct answer is option: 'A'.

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