Q74 / 160 · JIPMER 2004 · Chemistry

Two metals 'A' and 'B' have $\mathrm{E}_{\text {red }}^{\circ}$ value equal to 0.36 V and 1.23 V . What will be the correct cell equation?

  • Correct answer
    A
    $\mathrm{A}+\mathrm{B}^{2+} \longrightarrow \mathrm{A}^{2+}+\mathrm{B}$
  • B
    $\mathrm{A}^{2+}+\mathrm{B} \longrightarrow \mathrm{A}+\mathrm{B}^{2+}$
  • C
    Both (1) and (2)
  • D
    None of the above

Solution

From $E_{\text {red }}^{\circ}$. values, it is clear that $A$ is more electropositive than $B$ (as it has lesser $E^{\circ}{ }_{\text {red }}$ ), hence it can replace $B$ from its salt solution and act as anode in galvanic cell. Hence, correct cell equation will be: $A+B^{2+} \longrightarrow A^{2+}+B$

Hence, the correct answer is option: 'A'.

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