Two metallic plates form a parallel plate capacitor. The distance between the plate is 'd'. A metal sheet of thickness d/2 and of area equal to area…

Question

Two metallic plates form a parallel plate capacitor. The distance between the plate is 'd'. A metal sheet of thickness d/2 and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

MARKS Content Team · Accepted Answer

Correct answer: (B) 2:1. Before the metal sheet is inserted, capacitance is given by C=(ε_0A)/d. After the sheet is inserted, the system is equivalent to two capacitors in series, each of capacitance C^(')=(ε_0A)/d4=4C. The equivalent capacity is now 1/(C')=1/4C+1/4C⇒C'=2C. The ratio is C/(C')=1/2=1:2

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Two metallic plates form a parallel plate capacitor. The distance between the plate is 'd'. A metal sheet of thickness d2 and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

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