Q134 / 160 · WBJEE 2012 · Physics

Two infinite parallel metal planes, contain electric charges with charge densities $+\sigma$ and $-\sigma$ respectively and they are separated by a small distance in air. If the permittivity of air is $\varepsilon_{0}$, then the magnitude of the field between the two planes with its direction will be

  • A
    $\sigma / \varepsilon_{0}$ towards the positively charged plane
  • Correct answer
    B
    $\sigma / \varepsilon_{0}$ towards the negatively charged plane
  • C
    $\sigma /\left(2 \varepsilon_{0}\right)$ towards the positively charged plane
  • D
    0 and towards any direction

Solution

$E=\frac{\sigma}{2 \varepsilon_{0}}+\frac{\sigma}{2 \varepsilon_{0}}$ $E=\frac{\sigma}{\varepsilon_{0}}$ towards negative charged plate.

Hence, the correct answer is option: 'B'.

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