Two inductors A and B when connected in parallel are equivalent to a single inductor of inductance 1.5 H, and when connected in series are equivalent…

Question

Two inductors A and B when connected in parallel are equivalent to a single inductor of inductance 1.5 H, and when connected in series are equivalent to a single inductor of inductance 8 H. Find the difference in the inductances of A and B.

MARKS Content Team · Accepted Answer

Correct answer: (D) 4 H. When inductors are connected in parallel, 1/1.5=(1L_1+1L_2 ⋯1When inductors are connected in series, 8=L_1+L_2⇒L_1=8-L_2 ⋯2Putting the result of equation (2) in (1),1)/1.5=1/(8-L_2)+1L_2L2^2-8L_2+12=0L_2=6 H or 2H and L_1=2 H or 6 H Thus difference between the two inductance value is 6-2=4

Two inductors $A$ and $B$ when connected in parallel are equivalent to a single inductor of inductance $1.5 H$ , and when connected in series are equivalent to a single inductor of inductance $8 H$ . Find the difference in the inductances of $A$ and $B$ .

Solution

Relevant Questions