Two identical conducting wires $\mathrm{A O B}$ and $\mathrm{C O D}$ are placed at right angles to each other. The wire $\mathrm{AOB}$ carries an electric current $\mathrm{I_1}$ and $\mathrm{COD}$ carries a current $\mathrm{I_2}$. The magnetic field on a point lying at a distance ' $\mathrm{d}$ ' from $\mathrm{O}$, in a direction perpendicular to the plane of the wires $\mathrm{A O B}$ and $\mathrm{C O D}$, will be given by

• Correct answer
  A

  $\frac{\mu_0}{2 \pi}\left(\frac{\mathrm{I}_1+\mathrm{I}_2}{d}\right)^{1 / 2}$
• B

  $\frac{\mu_0}{2 \pi \mathrm{d}}\left(\mathrm{I}_1^2+\mathrm{I}_2^2\right)^{1 / 2}$
• C

  $\frac{\mu_0}{2 \pi d}\left(\mathrm{I}_1+\mathrm{I}_2\right)$
• D

  $\frac{\mu_0}{2 \pi d}\left(\mathrm{I}_1^2+\mathrm{I}_2^2\right)$

Hence, the correct answer is option: 'A'.