Q153 / 160 · JIPMER 2014 · Zoology

Two genes $R$ and $y$ are located very close on the chromosome linkage map on maize plant. When RRYY and rryy genotypes are hybridised, then $\mathrm{F}_2$ segregation will show

  • A
    higher number of the recombinant types
  • B
    Segregation with expected 9:3:3:1 ratio
  • C
    Segeragation is $3: 1$ ratio
  • Correct answer
    D
    higher number of the parental types

Solution

Law of independent assortment does not applicable when the gene of different character occupy on the same homologous chromosomes, i.e., linked genes.

Hence, the correct answer is option: 'D'.

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