Two forces of 5.0 N each are acting on a point mass. If the angle between the forces is 60^° , then the net force acting on the point mass has magnitude close to :

Correct answer: (A) 8.6 N. The net force acting on the point mass has magnitude close to F_net=√F_1^2+F_2^2+2 ~F_1 ~F_2 Cos 60^° (∵ F_1=F_2=5 ~N ) =√(5^2+5^2+2 × 5 × 5 × 1/2)=8.6 ~N

Q56 / 270 · NDA 2023 (Phase 1) · General Ability

Two forces of 5.0 N each are acting on a point mass. If the angle between the forces is $60^{\circ}$, then the net force acting on the point mass has magnitude close to :

Correct answer
A
8.6 N
B
4.3 N
C
5.0 N
D
6.7 N

Solution

The net force acting on the point mass has magnitude close to $\qquad$ $\mathrm{F}_{\mathrm{net}}=\sqrt{\mathrm{F}_1^2+\mathrm{F}_2^2+2 \mathrm{~F}_1 \mathrm{~F}_2 \operatorname{Cos} 60^{\circ}}\left(\because \mathrm{F}_1=\mathrm{F}_2=5 \mathrm{~N}\right)$ $=\sqrt{5^2+5^2+2 \times 5 \times 5 \times \frac{1}{2}}=8.6 \mathrm{~N}$

Hence, the correct answer is option: 'A'.

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