Q30 / 90 · JEE Main 2015 (04 Apr) · Chemistry

Two Faraday of electricity is passed through a solution of $C u S O_{4}$ . The mass of copper deposited at the cathode is: (Atomic mass of Cu = 63.5 amu)

A
$127 g$
B
$0 g$
Correct answer
C
$63.5 g$
D
$2 g$

Solution

${Cu}^{+ 2} + 2 e^{-} \to Cu$

2 Faraday charge deposits 1 mol of Cu, or

$2 F \equiv 2 Equivalents of Cu$

Mass of Cu deposited $= 2 \times \frac{63 .5}{2} = 63 .5 g$

Hence, the correct answer is option: 'C'.

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