Q78 / 160 · AP EAMCET 2013 · Mathematics
Two fair dice are rolled. The probability of the sum of digits on their faces to be greater than or equal to 10 is
- A$\frac{1}{5}$
- B$\frac{1}{4}$
- C$\frac{1}{8}$
- Correct answerD$\frac{1}{6}$
Solution
Total samle points, $n(S)=6 \times 6=36$
Favourable events
$$
=[(6,4),(6,5),(6,6),(5,5),(5,6),(4,6)]
$$
Total favourable events, $n(E)=6$
Required probability
$$
=\frac{n(E)}{n(S)}=\frac{6}{36}=\frac{1}{6}
$$
Hence, the correct answer is option: 'D'.