Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I=I_0sin⁡ωt, where I_0=10 A and ω=100π rad…

Question

Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I=I_0sin⁡ωt, where I_0=10 A and ω=100π rad s^(-1). The maximum value of emf in the second coil is

MARKS Content Team · Accepted Answer

Correct answer: (B) 5π. emf, induced in second coil e=MdI/dt ⇒ e=Md/dtI_0sin⁡ωt=MI_0ωcos⁡ωt ⇒ e=0.005×10×100πcos⁡ωt ⇒ e=5πcos⁡ωt, e_max=5π (emf is maximum for cos⁡ωt=1)

Two coils have a mutual inductance $0.005 H .$ The current changes in the first coil according to equation $I = I_{0} \sin (ω t),$ where $I_{0} = 10 A$ and $ω = 100 π rad s^{- 1} .$ The maximum value of emf in the second coil is

Solution

More Electromagnetic Induction Questions

Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I=I0sin⁡ωt, where I0=10 A and ω=100π rad s-1. The maximum value of emf in the second coil is

Solution

More Electromagnetic Induction Questions

Two coils have a mutual inductance $0.005 H .$ The current changes in the first coil according to equation $I = I_{0} \sin (ω t),$ where $I_{0} = 10 A$ and $ω = 100 π rad s^{- 1} .$ The maximum value of emf in the second coil is