Q30 / 68 · NTA Abhyas (JEE Main) 2020 · Physics · Electromagnetic Induction

Two coils are fixed in space at some distance from each other such that there is a flux linkage between them. When coil 1 has no current and the current in the coil 2 increases at the rate 15.0 A s-1, the emf in the coil 1 is 25.0 mV. When coil 2 has a current of 3.6 A, the flux linkage in coil 2 (in mWb) is 

Correct answer: 6

Solution

As e=Mdidt

∴  M=edi/dt=25×10-315.0=1.67×10-3H

As ϕ =Mi

∴ ϕ=1.67×10-3×3.6=6×10-3 Wb

       = 6 mWb

Hence, the correct answer is 6.

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