Two capacitors of capacitance C are connected in series. If one of them is filled with dielectric substance K, the effective capacitance is

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MARKS Content Team · Accepted Answer

Correct answer: (A) KC/((1+K)). When plates of capacitor are separated by a dielectric medium of dielectric constant K, its capacity C_m=(Kε_0A)/d=KC_0 ie, C_m=KC_0 Here, C_0=C ∴ C_m=KC Now, two capacitors of capacities KC and C are in series, their effective capacitance 1/(C^(′))=1/KC+1/C or 1/(C^(′)) =(1+K)/KC ∴ C^(′)=KC/(K+1)

Two capacitors of capacitance $C$ are connected in series. If one of them is filled with dielectric substance $K$ , the effective capacitance is

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