Q30 / 180 · AIIMS 2013 · Chemistry

Total number of antibonding electrons present in $\mathrm{O}_2$ will be

  • Correct answer
    A
    $6$
  • B
    $8$
  • C
    $4$
  • D
    $2$

Solution

$\begin{aligned} & \mathrm{O}_2(\sigma 1 s)^2\left(\sigma^* 1 s\right)^2(\sigma 2 s)^2\left(\sigma^* 2 s\right)^2\left(\sigma 2 p_z\right)^2\left(\pi 2 p_x^2=\pi 2 p_y^2\right) \\ & \left(\pi^* 2 p_x{ }^1=\pi^* 2 p_y^1\right)\end{aligned}$ Thus, there are total 6 electrons in antibonding orbitals

Hence, the correct answer is option: 'A'.

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