Toluene $\underset{\text { (2) } \mathrm{H}_3 \mathrm{O}^{+}}{\xrightarrow {\text {(1) } {\mathrm{CrO}_2 \mathrm{Cl}_2 / \mathrm{CS}_2}}} {\mathrm{X} \xrightarrow{\text { Conc. } \mathrm{NaOH}} \mathrm{Y}+\mathrm{Z}}$ The correct statements about Y and Z are A. $\quad \mathrm{Y}$ is a secondary alcohol B. $\quad \mathrm{Y}$ is the reduction product of X C. $\quad \mathrm{Z}$ on heating with soda lime gives benzene D. $\quad \mathrm{Y}$ does not give $\mathrm{H}_2$ gas with Na metal

• Correct answer
  A

  B & C only
• B

  A & B only
• C

  A & D only
• D

  B & D only

Hence, the correct answer is option: 'A'.