Q70 / 180 · AIIMS 2003 · Chemistry

Time required to deposit one millimole of aluminium metal by the passage of 9.65 amperes through aqueous solution of aluminium ion is

  • A
    $30 \mathrm{~s}$
  • Correct answer
    B
    $10 \mathrm{~s}$
  • C
    $30,000 \mathrm{~s}$
  • D
    $10,000 \mathrm{~s}$.

Solution

$ \mathrm{Al}^{3+}+3 e^{-} \rightarrow \mathrm{Al}$ For deposition of $1 \mathrm{~g}$ equivalent $\equiv 96500 \mathrm{C}$ For deposition of 1 millimole $\equiv 96.500 \mathrm{C}$ As $Q=I t \Rightarrow t=\frac{Q}{I}=\frac{96.5}{9.65}=10 \mathrm{~s}$

Hence, the correct answer is option: 'B'.

Relevant Questions