Q110 / 180 · NEET 2016 (Phase 2) · Physics

Three sound waves of equal amplitudes have frequencies, $(n - 1), n, (n + 1)$ . They superimpose to give beats. The number of beats produced per second will be

A
$1$
B
$4$
C
$3$
Correct answer
D
$2$

Solution

Number of beats $= 2$ .

Maximum difference between the given frequencies.

Hence, the correct answer is option: 'D'.

Relevant Questions

In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz . When tension in B is s2020 (Phase 1)Beats
A source of unknown frequency gives 4 beats/s when sounded with a source of known frequency . The second harmonic of the source of unknown f2013 (All India)Beats
Two source and produce notes of frequency each. A listener moves from to with a speed of . If the speed of sound is , then the number of bea2013 (Karnataka)Beats
Two sources of sound placed close to each other, are emitting progressive waves given by An observer located near these two sources of sound2012 (Screening)Beats
Two identical piano wires kept under the same tension have a fundamental frequency of . The fractional increase in the tension of one of the2011 (Mains)Beats
A tuning fork of frequency makes 4 beats/seconds with the vibrating string of a piano. The beat frequency decreases to 2 beats/s when the te2010 (Screening)Beats