Q35 / 120 · NEET 2010 (Mains) · Chemistry

Three moles of an ideal gas expanded spontaneously into vacuum. The work done will be

A
infinite
B
$3 \mathrm{~J}$
C
$9 \mathrm{~J}$
Correct answer
D
zero

Solution

$W=\mathrm{p}_{\text {ext }} \cdot \Delta \mathrm{V}$ For vacuum, $\quad \mathrm{P}_{\text {ext }}=0$ $\therefore \quad \mathrm{W}=0 \cdot \Delta \mathrm{V}=0$

Hence, the correct answer is option: 'D'.

Relevant Questions

Consider the following reaction : kJ mol and J K at K. Identify the correct option with for the reaction and spontaneity of the reaction at 2026 (Cancelled)First Law and Basic Fundamentals of Thermodynamics
At a certain temperature, (K), during a process, J is absorbed by the system and work of J is done by the system. Then, change in internal e2026 (Cancelled)First Law and Basic Fundamentals of Thermodynamics
Consider the reversible processes for mol of an ideal gas as shown in the figure. Processes 2 and 4 are adiabatic. , , and represent work do2026 (Re-NEET)First Law and Basic Fundamentals of Thermodynamics
Match List I with List II. Choose the correct answer from the options given below:2024First Law and Basic Fundamentals of Thermodynamics
The work done during reversible isothermal expansion of one mole of hydrogen gas at from pressure of 20 atmosphere to 10 atmosphere is (Give2024First Law and Basic Fundamentals of Thermodynamics
Choose the correct statement for the work done in the expansion and heat absorbed or released when 5 litres of an ideal gas at 10 atmospheri2024 (Re-NEET)First Law and Basic Fundamentals of Thermodynamics