Three forces F_1=10 N, F_2=8 N, F_3=6 N are acting on a particle of mass 5 kg. The forces F_2 and F_3 are applied perpendicularly so that particle…

Question

Three forces F_1=10 N, F_2=8 N, F_3=6 N are acting on a particle of mass 5 kg. The forces F_2 and F_3 are applied perpendicularly so that particle remains at rest. If the force F_1 is removed, then the acceleration of the particle is

MARKS Content Team · Accepted Answer

Correct answer: (D) 2 m s^(–2). When the force F_1 is removed, the particle starts accelerating because of the resultant force between F_2 and F_3. The resultant force can be calculated as follows: F = √(F2^2+F3^2) = 10 N Hence, the acceleration of the particle is given by a = (10 N)/(5 kg) = 2 m s^(–2)

Three forces $F_{1} = 10 N, F_{2} = 8 N, F_{3} = 6 N$ are acting on a particle of mass $5 kg$ . The forces $F_{2}$ and $F_{3}$ are applied perpendicularly so that particle remains at rest. If the force $F_{1}$ is removed, then the acceleration of the particle is

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Relevant Questions

Three forces F1=10 N, F2=8 N, F3=6 N are acting on a particle of mass 5 kg. The forces F2 and F3 are applied perpendicularly so that particle remains at rest. If the force F1 is removed, then the acceleration of the particle is

Solution

Relevant Questions

Three forces $F_{1} = 10 N, F_{2} = 8 N, F_{3} = 6 N$ are acting on a particle of mass $5 kg$ . The forces $F_{2}$ and $F_{3}$ are applied perpendicularly so that particle remains at rest. If the force $F_{1}$ is removed, then the acceleration of the particle is