Q231 / 270 · NDA 2013 (Phase 2) · Mathematics

Three dice are thrown. What is the probability of getting a triplet?

  • A
    $\frac{1}{6}$
  • B
    $\frac{1}{18}$
  • Correct answer
    C
    $\frac{1}{36}$
  • D
    $\frac{1}{72}$

Solution

$\begin{aligned} \text { Sample event }=(1,1,1), & (2,2,2),(3,3,3),(4,4,4),(5,5,5),(6,6,6)\end{aligned}$ $n(\mathrm{E})=6$ Sample space $=6 \times 6 \times 6, n(s)=216$ $p(\varepsilon)=\frac{n(\mathrm{E})}{n(s)}=\frac{6}{216}=\frac{1}{36}$

Hence, the correct answer is option: 'C'.

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