Three blocks are pushed with a force $\mathrm{F}$ across a frictionless table as shown in figure. Let $\mathrm{N}_{1}$ be the contact force between the left two blocks and $\mathrm{N}_{2}$ be the contact force between the right two blocks. Then

• Correct answer
  A

  $F>N_{1}>N_{2}$
• B

  $F>N_{2}>N_{1}$
• C

  $\quad F>N_{1}=N_{2}$
• D

  $F=N_{1}=N_{2}$

Solution

$\mathrm{F}=6 \mathrm{a}, \mathrm{N}_{1}=5 \mathrm{a}, \mathrm{N}_{2}=3 \mathrm{a}$ $\mathrm{F}>\mathrm{N}_{1}>\mathrm{N}_{2}$

Hence, the correct answer is option: 'A'.