Q75 / 90 · JEE Main 2012 (07 May Online) · Physics

This question has Statement 1 and Statement 2. Of the four choices given after the Statements, choose the one that best describes the two Statements. Statement 1: In an adiabatic process, change in internal energy of a gas is equal to work done on/ by the gas in the process. Statement 2: The temperature of a gas remains constant in an adiabatic process.

  • A
    Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation of Statement 1.
  • Correct answer
    B
    Statement 1 is true, Statement 2 is false.
  • C
    Statement 1 is false, Statement 2 is true.
  • D
    Statement 1 is false, Statement 2 is true, Statement 2 is not a correct explanation of Statement 1.

Solution

In an adiabatic process, $\delta \mathrm{H}=0$ And according to first law of thermodynamics $$ \begin{aligned} & \delta H=\delta U+W \\ & \therefore W=-\delta U \end{aligned} $$

Hence, the correct answer is option: 'B'.

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