Q41 / 120 · VITEEE 2013 · Mathematics
Therelation $R$ defined on set $\mathrm{A}=\{x:|x| < 3, x \in \mathrm{I}\}$ by $R=\{(x, y): y=|x|\}$ is
- Correct answerA$\{-2,2),(-1,1),(0,0),(1,1),(2,2)\}$
- B$\{(-2,-2),(-2,2),(-1,1),(0,0),(1,-2),(1,2)$, $(2,-1),(2,-2)\}$
- C$\{0,0),(1,1),(2,2)\}$
- DNone of the above
Solution
$\begin{array}{l}
A=\{x:|x| < 3, x \in I\} \\
A=\{x:-3 < x < 3, x \in I\}=\{-2,-1,0,1\} \\
\text { Also, } R=\{(x, y): y=|x|\} \\
\therefore R=\{(-2,2),(-1,1),(1,1),(0,0),(2,2)\}
\end{array}$
Hence, the correct answer is option: 'A'.