Q48 / 98 · NTA Abhyas (JEE Main) 2020 · Mathematics · Permutation Combination

There are 7 distinguishable rings. The number of possible five-rings arrangements on the four fingers (except the thumb) of one hand (the order of the rings on each finger is to be counted and it is not required that each finger has a ring) is equal to

  • A
    214110
  • B
    211410
  • C
    124110
  • Correct answer
    D
    141120

Solution

There are 7C5 ways of selecting the rings to be worn.
If a,b,c,d are the number of the rings on the fingers, we need to find the non-negative integers such that a+b+c+d=5. 
The numbers of such quadruples is 5+4-1C4-1=8C3.
For each set of 5 rings, there are 5! arrangements.
So, the total number of required arrangements is 7C5×8C3×5!=141120

Hence, the correct answer is option: 'D'.

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