Q1 / 120 · VITEEE 2019 · Chemistry
The work done in ergs for the reversible expansion of one mole of an ideal gas from a volume of 10 litres to 20 litres at $25^{\circ} \mathrm{C}$ is
- A$2.303 \times 298 \times 0.082 \log 2$
- Correct answerB$298 \times 10^{7} \times 8.31 \times 2.303 \log 2$
- C$2.303 \times 298 \times 0.082 \log 0.5$
- D$8.31 \times 10^{7} \times 298-2.303 \log 0.5$
Solution
$$
\begin{aligned}
\mathrm{W} &=2.303 \mathrm{nRT} \log \frac{\mathrm{V}_{2}}{\mathrm{~V}_{1}} \\
&=2.303 \times 1 \times 8.314 \times 10^{7} \times 298 \log \frac{20}{10} \\
&=298 \times 10^{7} \times 8.31 \times 2.303 \log 2
\end{aligned}
$$
Hence, the correct answer is option: 'B'.